Question

find three different solutions of the following equations
1)4x+3y=7
2)x=6y
3)x-2y=5
4)2x+4y=1​
please guys don't spam the answer if you don't know don't answer please you know only answer let the people who know answer thank you please understand ​​​​

Answer 1

Answer:

wer: ( 0, \dfrac{7}{3}

3

7

) and (1,1) are different solution of the given equation.

Step-by-step explanation:

To find: The different solution of 4x+3y= 7

For the solution Let

i) x = 0 in the given equation

\begin{gathered}4\times 0 + 3y = 7 \\\\\Rightarrow y = \dfrac{7}{3}\end{gathered}

4×0+3y=7

⇒y=

3

7

therefore ( 0, \dfrac{7}{3}

3

7

) is the solution of given equation

ii) Now let x= 1

\begin{gathered}4\times 1 + 3y = 7 \\\\\Rightarrow 3y= 7-4\\\\\Rightarrow 3y=3 \Rightarrow y= 1\end{gathered}

4×1+3y=7

⇒3y=7−4

⇒3y=3⇒y=1

Therefore (1,1) is the solution of equation

. this is a

Answer 2

Answer:

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Step-by-step explanation:

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