Math, asked by shivashanka, 3 months ago

Find three different solutions of the following equations.

A) 4x+3y=7 B) x=6y C) x2y=5 D) 2x+4y=1​

Answers

Answered by Akankshya2106
11

Step-by-step explanation:

A) 4x+3y = 7

x = 0

4×0 + 3y = 7

0+3y = 7

y = 7/3

(0,7/3)

x = 1

4×1 + 3y = 7

4+3y = 7

3y = 7-4

3y = 3

y = 3/3

y = 1

(1,1)

x = 2

4×2 + 3y = 7

8 + 3y = 7

3y = 7-8

3y = -1

y = -1/3

(2,-1/3)

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