Math, asked by ubaid225, 9 hours ago

find three irrational numbers between 0.2101 and 0.2222... explain​

Answers

Answered by ujjwalbrainy
1

That is, in the decimal expansion of number a the third digit is 0 and in the decimal expansion of number b the third digit is 2 . ... Hence, the required irrational number is 0.220… or 0.221… between 0.2101 and 0.2222… . That is, the required irrational number is 0.22010010001… .

Answered by islegend12345
0

Step-by-step explanation:

in the decimal expansion of number a the third digit is 0 and in the decimal expansion of number b the third digit is 2 . ... Hence, the required irrational number is 0.220… or 0.221… between 0.2101 and 0.2222… . That is, the required irrational number is 0.22010010001

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