Question

find three irrational numbers between 7/4 , 11/6​

Answer 1

Answer:

$\frac{7}{4} = \frac{21}{12} = \sqrt{ \frac{441}{144} }$

$\frac{11}{6} = \frac{22}{12} = \sqrt{ \frac{484}{144} }$

so required irrational numbers are

$\sqrt{ \frac{442}{144} } \: or \: \sqrt{ \frac{443}{144} } \: or \: \sqrt{ \frac{444}{144} } \: or \: \sqrt{ \frac{483}{144} }$