Question

Find three natural consecutive numbers such that the sum of the first and the second is 15 more than the third​

Answer 1

Answer:Numbers = 16, 17, 18

Step-by-step explanation:

Let numbers = x, x+1, x+2

x + x + 1 = x + 2 + 15

=> 2x = 17 + x - 1

=> x = 16

Numbers = 16, 17, 18

Answer 2

Answer:

7+8+9=24

Step-by-step explanation:

(x+1+x+2)=18 (more than 15)

x3=18

x=18÷3

x=6

(6+1)+(6+2)+(6+3)

7+8+9=

24

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