Question

find three natural numbers whose sum and product are equal
n(A)=25, n(B)+30, n(AUB) = 50 find A intersection B

Answer 1

Answer:

1,2&3.

Sum: 1+2+3=6

Product:1×2×3=6.

So the sum of 1,2 and 3 is equal to their product also.

Given that

n(A)= 26

n(B)= 30

n(AUB)= 50

n(A intersection B)= ?

As we know that

n(A intersection B)= n(A)+n(B)-n(AUB)

= 26+30-50

= 56-50= 6

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