find three no in GP such that their sum is 42 and their product is 1728
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Answered by
1
Answer:
Explanation:
Let the no a/ r,a and at product of 1728.
a/r *a*ar1728
A3 =12
12 / r +12+12r=38
12+12r+12r2 =38r
12 r2 -26r+12=0
6r2 -13r+6=0
R= 2/3 and 3/2
Answered by
3
Explanation:
hope it may help you ...
req. no in gp are 6,12,24
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