Question

Find three nos in ap whose sum is 21 and product is 315

Answer 1

Answer:

a=5,b=7,c=9

Step-by-step explanation:

a+b+c=21

a×b×c=315

then a,b,c=?

Given,that the numbers are in arthemetic progression

so, a+(2+a)+(4+a)=21

3a+6=21

3a=15

a=5

b=2+a=5+2=7

c=4+a=4+5=9

Check:-

(a+b+c=21)

5+7+9=21

a×b×c=315

5×7×9=315

So,the question is solved