Math, asked by RupalShah, 1 year ago

Find three number in the ratio 2:3:5: the sum of whose square is 608​

Answers

Answered by JyotirmayeeMohanta
8

Answer:

hope it helps you....^_^

Attachments:
Answered by sajisharoon
3

Answer:

32, 48, 50.

Step-by-step explanation:

The unknown number is - 2²x + 3²x + 5²x = 608

4x + 9x + 25x = 608

38x = 608

x = 608/38

x = 16

x = √16 = 4

Hence, the three number are : - 2x = 2 × 4 = 8

                                                     3x = 3 × 4 = 12

                                                     5x = 5 × 4 = 20

Please mark me brillanest and hope this answer helps you.

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