Question

find three number in the ratio 2:3:5, the sum of whose square is 608​

Answer 1

Answer:

let the three numbersa, b, c, be 2x, 3x, 5x.

we know that

(2x) ^2+ (3x) ^2 + (5x)^2= 608

4x^2 + 9x^2 + 25x^2 = 608

38x^2 = 608

x^2= 608/38

x^2=16

x= √16

x= 4

a= 2x = 2*4=8

b=3x= 3*4=12

c = 5x= 5*4=20

therefore, the three numbers are 8,12,20

Step-by-step explanation: