find three number of ap whose sum is 24 and sum of square is 210
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let the 3 numbers be
a−d,a,a+d
Sum =24
if 3a=24
a=8
∴ the numbers are
(8−d),8,(8+d)
Sum of squares a=210
(8-d)² + 8² + (8+d)² = 210
3(8)² + 2d² = 210
2d² = 210 - 192
d² = 18/2
d = √9
d = ± 3
if d = + 3 the no. are = 8+3, 8 - 3 ,8
5 , 08 , 11
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