Question

Find three number such that the product of the first and the second is 28, product of the second and the third is 84 and the product of the third and first is 48.

Answer 1

Let first number be x, second be y and third be z.

So according to question,

xy = 28 .. I.

yz = 84 .. II.

Divide II by I.

yz/ xz = 84/28

z/x = 3. .. III

Since xz = 48 given .. IV

Multiply III by IV

z/ x * xz = 48*3

z^2 = 144

z = 12.

Put value of x in equation IV and II to find value of x and y.

yz = 84

y= 84/z = 84/12

= 7.

xz = 48

= x = 48/z = 48/12

=4.

Hence first number is 4, second is 7 and third is 12.

Hope it's helpful to u.

Answer 2

Answer:

Hope the attachment will help you