find three number whose sum is 12 and sum of their cubes is 408
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the answer is 1 8 3
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Let one number be x
Another number be 12-x
Another number is
408-(×^3)-(12-x)^3 =0
Solve and you may get the answer
Another number be 12-x
Another number is
408-(×^3)-(12-x)^3 =0
Solve and you may get the answer
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