Question

find three numbers between 17 and 27 such that they are in A.p with 17 and 27 .​

Answer 1

The answer is "19.5, 22, 24.5 "

Step-by-step explanation:

The first number is here = 17 = a

The 5th number is = 27.

By using  tn= a+(n-1) d.

therefore t5= a + (5-1) d

  27= 17 + 4d

   4d = 10

d= 2.5

then t2= t1+d = 17+2.5 = 19.5

        t3 = t2+d= 19.5+2.5 = 22

       t4= t3+ d = 22 + 2.5 = 24.5

Then the A.P. is 17, 19.5, 22, 24.5, 27....

Answer 2

Answer:

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Step-by-step explanation:

The answer is "19.5, 22, 24.5"

The first number is here = 17 = a

The 5th number is = 27.

By using tn=a+(n-1) d.

therefore t5= a + (5-1) d

27= 17 + 4d

4d = 10

d= 2.5

then t2= t1+d=17+2.5 19.5

t3 t2+d= 19.5+2.5 = 22

t4= t3+ d = 22 +2.5 = 24.5

Then the A.P. is 17, 19.5, 22, 24.5, 27....