Question

Find three numbers between 17 and 27 that are in arithmetic order with 17 and 27

Answer 1

Answer:

17,39/2,22,49/2,27

Step-by-step explanation:

t1=17 ,tn=27, n=5

we know that,

tn=a+(n-1)d

27=17+(5-1)d

27-17=4d

10=4d

10/4=d

5/2=d

t1=17

t2=t1 +d=17+5/2=39/2

t3=t2+d=39/2+5/2=44/2=22

t4=t3+d=22+5/2=49/2

t5=27

Answer 2

Given:

Two numbers, 17 and 27.

To find:

Three numbers between 17 and 27 which are in arithmetic order with 17 and 27.

Solution:

We can solve the above mathematical problem with this mathematical approach.

$The first number is =17=a \\The 5th number is =27 \\By using t_n= a+(n-1) d\\ Therefore, t_5=a+(5-1) d$

$\begin{array}{c}27 = 17+4 d \\4 d=10 \\ common difference = d=2.5\end{array} \text { then, }\\ \begin{array}{r}t 2=t 1+d=17+2.5=19.5 \\t 3=t 2+d=19.5+2.5=22 \\t 4=t 3+d=22+2.5=24.5\end{array} A.P. is 17,19.5,22,24.5,27 .$

Therefore, the A.P. is 17, 19.5, 22, 24.5, 27.