find three numbers in A.P whose sum is 15 and the sum of their squares is 83
Answers
Answered by
9
3a = 15
a = 15 / 3
a = 5
product = 80
( a - d ) a ( a + d ) = 80
( a² - d² ) a = 80
( 5² - d² ) 5 = 80
25 - d² = 80 /5
25 - d² = 16
- d² = - 9
d² = 3²
d = ± 3
Therefore,
a = 5 , d = ±3
required 3 terms are
a - d = 5 - 3 = 2
a = 5
a+ d = 5 + 3 = 8
( 2 , 5 , 8 ) or ( 8 , 5 , 2 )
I hope this helps you.
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Answered by
3
3a=15
a=15/3
A
a=5
Product = 80
(a-d)a(a+d)=80
(a²-d²)a=80
(5²-d²)5=80
25-d²=16
-d²=3²
d=±3
Therefore,
a=5,d=±3
Required 3 terms
(2,5,8) (8,5,2)
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