Find three numbers in A.P. whose sum is 24 and product 44
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let the no. be a+d, a, a-d
Sn=24
a+d +a+ a-d=24
3a=24
a=8
it's products is 44
a(a+d)(a-d)=44
a(a²-d²)=44
8(64-d²)=44
64-d²=44÷8
-d²=5.5-64
-d²=-58.5
d²=58.5
d=±7.65
we get the value of a=8 and d=+7 .65
a+d
8+7.65
15.65
a=8
a-d
8-7.65
0.35
15.65,8,0.35 are the no.s or u can take d=-7.65 then no.s will 0.35,8,15.65
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