Find three numbers in A.P. whose sum is 6 and the sum of whose square is 44.
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Answer:
Let the number be
a‐d,a,a,d
a-d+a+a+d=6
3a=6
a=2
(a-d)²+a²+(a+d)²=44
(2-d)²+2²+(2+d)²=44
(2-d)²+4+(2+d)²=44
4-d²-4d+2d²+4+4+d²+4d+2d²=44
8+4d²=44
4d²=44-8
d²=36/4
d²=9
Nos. are 9+root 9,9,9-root9 or
9-root 9,9,9+root 9
I hope you understand
With Regard
Ayush Sinha
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