Question

Find three numbers in an AP such that their sum is 30 and product is 960.
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Answer 1

Answer:

8,10,12 or 12,10,8

Step-by-step explanation:

let numbers be A-D,A,A+D

sum=3A=30

A=10

product =(A-D)(A)(A+D)=960

=(A^2-D^2)10 =960

=100-D^2 =96

=D^2=4

=D=2 or -2

so AP is 8,10,12 or 12,10,8

Answer 2

Step-by-step explanation:

Let the numbers be x, x+y,and x+2y

So, x+x+y+x+2y=30

3(x+y)=30

x+y=10

Now x×(x+y)×(x+2y)=960

x×10×(10+y)=960

10x +xy=96

Now,10x+xy-x-y=96

9x+xy-y=96

After this by applying quadratic equation you can solve this...