Math, asked by ak5608182, 9 months ago

find three numbers in AP so that their sum is 21 and the product of the last two is 84​

Answers

Answered by kaushikumarpatel
1

Answer:

Let the numbers in AP be a - d, a, a + d

a - d + a + a + d = 21

3 a = 21

a = 7

a (a + d) = 84

a^2 + a d = 84

(7)^2 + 7 * d = 84

7 * d = 84 - 49

7 d = 35

d = 5

Hence the AP is 2, 7, 12

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