find three numbers in AP so that their sum is 21 and the product of the last two is 84
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Let the numbers in AP be a - d, a, a + d
a - d + a + a + d = 21
3 a = 21
a = 7
a (a + d) = 84
a^2 + a d = 84
(7)^2 + 7 * d = 84
7 * d = 84 - 49
7 d = 35
d = 5
Hence the AP is 2, 7, 12
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