Math, asked by aryamalik274, 10 months ago

Find three numbers in ap whose sum 3 and product is -35

Answers

Answered by bhoirpooja2004
4

Answer:

Step-by-step explanation:

let (a-d), a,(a+d) are three numbers in a.p.

from 1st condition ,

(a-d)+a+(a+d)=3

3a=3

a=1

from 2nd condition ,

(a-d).a.(a+d)=-35

(a)squqre-(d)square=-35

1-(d)square=-35

35+1=(d)square

d=6

a-d=1-6=-5

a=1

a+d=1+6=7

therefore, three numbers in a.p. are -5,1,7

Answered by surinderpahuja
0

Answer:

a = 1

a = 1 d = 6

Step-by-step explanation:

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