Math, asked by danvirparmar983, 7 months ago

Find three numbers in AP whose Sum is 15 and the no
whose product is 35 find the number​

Answers

Answered by Preetlotey96
1

Answer:

I just can't solve this question but I tried this as it in pic....

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Answered by ciola
0

Step-by-step explanation:

Let us assume three numbers as :

(a - d), \:  \: (a), \:  \: (a + d) \\

The Sum of three numbers is 15

(a - d) + (a) + (a + d) = 15 \\

Then the First number ‘a’ is :

(a - d) + (a) + (a + d) = 15 \\ a - d + a + a + d = 15 \\  a \cancel{ - d} + a + a + \cancel d = 15 \\ 3a = 15 \\ a =  \frac{15}{3}  \\ \boxed{ a = \underline{ \underline{\bf 5}}} \\

The Product of three numbers is 35

(a - d) \times (a) \times (a +d) = 35 \\

Then the Common difference ‘d’ is :

(a - d)(a)(a + d) = 35 \\ (5 - d)(5)(5 + d) = 35 \\ 5(5 - d)(5 + d) = 35 \\ 5( {5}^{2}  -  {d}^{2} ) = 35 \\ 5(25 -  {d}^{2} ) = 35 \\ 25 -  {d}^{2}  = 35 \div 5 \\ 25 -  {d}^{2}  = 7 \\ 25 - 7 =  {d}^{2}  \\ 18 =  {d}^{2}  \\  \sqrt{18}  = d \\  \sqrt{9 \times 2}  = d \\  \sqrt{ {3}^{2} \times 2 }  = d \\ \boxed{ \underline{ \underline{ \bf 3 \sqrt{2}}}  = d} \\

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