Find three numbers in ap whose sum is 6 and the sum of their cubes is 232
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Step-by-step explanation:
Let the numbers are 2 – d, 2 and 2 + d
(2–d)³+ (2+d)³ = 232 – 8 = 224
or, 8 – 12d + 6d² – d³ + 8 + 12d + 6d² + d³ = 224
or, 16 + 12d² = 224
or, d² = 208/12 = 52/3
numbers are 2 – √(52/3), 2 and 2 + √(52/3)
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