Question

Find three numbers in G.P. such that their sum is 35 and their product is 1000.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Three numbers are 5,10,20

Step-by-step explanation:

In this question

We have been given that

Sum of three numbers of G.P are 35 and their product is 1000.

We need to find the Three numbers which are in G.P

Let three numbers of G.P are $\frac{a}{r},a,ar$

Product of 3 numbers

$a.\frac{a}{r}.ar\ =\ 1000$

$a^{3}\ =\ 1000$

$a\ =\ 10$

a = 10

Sum of three numbers is 35

Therefore, $\frac{a}{r}\ +\ a\ +\ ar\ =\ 35$

Putting the value of a as 10 we get,

$\frac{10}{r}\ +\ 10\ +\ 10r\ =\ 35$

Taking L.C.M we get,

$10r^{2}\ +\ 10r\ +\ 10\ =\ 35r$

$10r^{2}\ -\ 25r\ +\ 10\ =\ 0$

$2r^{2}\ -\ 5r\ +\ 2\ =\ 0$

On solving we get r = $2,\frac{1}{2}$

Putting the value of a and r simultaneously we get,

5,10,20 as three numbers