Math, asked by sangsangyee18, 7 months ago

Find three numbers in GP whose sum ii 38 and whose product is 1728​

Answers

Answered by 24Nikhil
2

Answer:

Step-by-step explanation:

let the numbers are a/r, a and ar

product = 1728

⇒ a/r * a * ar = 1728

⇒ a³ = 1728

⇒ a = 12

12/r + 12 + 12r = 38

⇒ 12 + 12r + 12r² = 38r

⇒ 12r² - 26r + 12 = 0

⇒ 6r² - 13r + 6 = 0

r = 2/3 and 3/2

numbers are  8, 12 and 18

Answered by aviralkachhal007
2

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