Find three numbers in GP. Whose sum is 65 and whose product is 3375
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the three numbers be .
∴ According to the question
⇒ …(1)
⇒ …(2)
From 2 we get,
⇒ a3 = 3375
∴ a = 15.
From 1 we get,
⇒
⇒ a + ar + ar2 = 65r …(3)
Substituting a = 15 in 3 we get
⇒ 15 + 15r + 15r2 = 65r
⇒ 15r2 – 50r + 15 = 0…(4)
Dividing (4) by 5 we get
⇒ 3r2 – 10r + 3 = 0
⇒ 3r2 – 9r – r + 3 = 0
⇒ 3r(r – 3) – 1(r – 3) = 0
∴ r = 3 or r = 1/3
∴ Now the equation will be
⇒
⇒ 5,15,45 or 45,15,5.
∴ The three numbers are 5,15,45.
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