Question

find three numbers in the ratio 2:3:5:, the sum of whose squares is 608.

Answer 1

let the three numbersa, b, c, be 2x, 3x, 5x.
we know that
(2x) ^2+ (3x) ^2 + (5x)^2= 608
4x^2 + 9x^2 + 25x^2 = 608
38x^2 = 608
x^2= 608/38
x^2=16
x= √16
x= 4
a= 2x = 2*4=8
b=3x= 3*4=12
c = 5x= 5*4=20
therefore, the three numbers are 8,12,20

Answer 2

I hope this solution would help you.