Question

Find three numbers in the ratio 2:3:5,the sum of whose square is 608.

​

Answer 1

Answer:

8,12,20

Step-by-step explanation:

let the three numbers a, b, c, be 2x, 3x, 5x.

we know that ,

(2x) ^2+ (3x) ^2 + (5x)^2= 608

4x^2 + 9x^2 + 25x^2 = 608

38x^2 = 608

x^2= 608/38

x^2=16

x= √16

x= 4

a= 2x = 2*4=8

b=3x= 3*4=12

c = 5x= 5*4=20

therefore, the three numbers are 8,12,20

plz mark as brainliest ™

Answer 2

Answer:

Let them

2x,3x and 5x

So

$(2x)^2 +(3x)^2+ (5x)^2=608$

$4x^2 +9x^2+25x^2=608$

$38x^2 =608$

$x^2=36$

$x=4$

The number are :-

• 2x =8
• 3x=12
• 5x=20