Question

Find three numbers in the ratio 2:3:5, the sum of whose squares is 608

Answer 1

Step-by-step explanation:

Let the three numbersa, b, c, be 2x, 3x, 5x.

we know that

(2x) ^2+ (3x) ^2 + (5x)^2= 608

4x^2 + 9x^2 + 25x^2 = 608

38x^2 = 608

x^2= 608/38

x^2=16

x= √16

x= 4

a= 2x = 2*4=8

b=3x= 3*4=12

c = 5x= 5*4=20

Therefore, the three numbers are 8,12,20

Answer 2

Answer:

32, 48, 50.

Step-by-step explanation:

The unknown number is - 2²x + 3²x + 5²x = 608

4x + 9x + 25x = 608

38x = 608

x = 608/38

x = 16

x = √16 = 4

Hence, the three number are : - 2x = 2 × 4 = 8

                                                     3x = 3 × 4 = 12

                                                     5x = 5 × 4 = 20

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