Question

Find three numbers in the ratio 2:3:5 the sum of whose squares is608

Answer 1

$\huge \mathfrak \colorbox{red}{answer}$

➡️let the three numbersa, b, c, be 2x, 3x, 5x. we know that

➡️(2x)^2+ (3x)^2 + (5x)^2= 608 4x^2 + 9x^2 + 25x^2 = 608

➡️38x^2 = 608

➡️x^2= 608/38

➡️x^2=16

➡️X= V16

➡️X= 4

➡️a= 2 x = 2*4=8

➡️b=3x= 3*4=12 c = 5x= 5*4=20

➡️therefore, the three numbers are

$\huge \colorbox{red}{8.12.20}$