Question

Find three numbers in the ratio 2:3:5, the sum of whose squares is 608.

Answer 1

Answer:

Step-by-step explanation:

let the three numbersa, b, c, be 2x, 3x, 5x.

we know that

(2x) ^2+ (3x) ^2 + (5x)^2= 608

4x^2 + 9x^2 + 25x^2 = 608

38x^2 = 608

x^2= 608/38

x^2=16

x= √16

x= 4

a= 2x = 2*4=8

b=3x= 3*4=12

c = 5x= 5*4=20

therefore, the three numbers are 8,12,20

Answer 2

HEY MATE ♡♡

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HERE IS YOUR ANSWER :

Let the numbers be 2x,3x and 5x

According to the question

(2x)^2+(3x)^2+(5x)^2=608
4x^2+9x^2+25x^2=608
38x^2=608
x^2=608/38
x^2=16
x=4

2x=2×4=8
3x=3×4=12
4x=4×4=16

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HOPE IT HELPED YOU ^_^