Math, asked by NodSambhav01, 7 months ago

.Find three numbers in the ratio 3:4:5, the sum of whose squares is 1800.

Answers

Answered by itugoswami123
3

Answer:

60

Step-by-step explanation:

Let the no.s be 3x,4x,5x then,

9x

2

+16x

2

+25x

2

=1250

⟹50x

2

=1250

⟹x=5

Sum of numbers =3x+4x+5x=12x=12×5=60

Answered by RiddhimanSaha02
1

Answer:

18 , 24 and 30

Step-by-step explanation:

Let the numbers be 3x , 4x and 5x.

Therefore according to question

3x^2 + 4x^2 + 5x^2 = 1800

9x^2 + 16x^2 + 25x^2 = 1800

50x^2 = 1800

x^2 = 1800/50

x^2 = 36

x = underoot 36

x = 6

Therefore First No. = 3 * 6 = 18

Second No. = 4 * 6 = 24

Third No. = 5 * 6 = 30

Have a nice day

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