Question

find three numbers such that the product of the first and the second is 24,second and the third is 48 and the first and the third is 32​

Answer 1

Answer:

Let first number be x, second be y and third be z.

So according to question,

xy = 28 .. I.

yz = 84 .. II.

Divide II by I.

yz/ xz = 84/28

z/x = 3. .. III

Since xz = 48 given .. IV

Multiply III by IV

z/ x * xz = 48*3

z^2 = 144

z = 12.

Put value of x in equation IV and II to find value of x and y.

yz = 84

y= 84/z = 84/12

= 7.

xz = 48

= x = 48/z = 48/12

=4.

Hence first number is 4, second is 7 and third is 12.

Hope it's helpful to u.

Answer 2

Answer:

Step-by-step explanation:

The numbers maybe 12 7 and 4