Question

Find three numbers, which are in the ratio 2: 3: 5 and the sum of square is 608.​

Answer 1

Answer:

Therefore, the numbers are 8,12 and 20.

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Answer 2

Let us assume the three number be 2a, 3a, 5a

Then,

Given, sum of squares of three numbers is 608

i.e. (2a)2 + (3a)2 + (5a)2 = 608 4a2 + 9a2 + 25a2

= 608 38a2

= 608 a2

= 608/38 a2

= 16 a

= √16 a

= √(4 × 4) a

= √(52) a

= 4

∴The numbers are,

2a = 2 × 4

= 8 3a

= 3 × 4

= 12 5a

= 5× 4

= 20

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