Question

Find three numbers which are in the ratio 2:3:5 such that sum of theirsquarrs is 608

Answer 1

Let the numbers be 2x,3x and 5x

Given

2x2 +3x2+5x2 = 608

=>4x2 +9x2+25x2 =608

=>38x2=608

=>x2=16 =>x= root of 16 =4

.

. . the numbers are 2x =2*4=8 ,

3x =3*4 =12 & 5x = 5*4 =20

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