Question

Find three positive integer in AP such that their sum is 30 and their product is 960...

Answer 1

Answer:

8,10,12

Step-by-step explanation:

LET the threw numbers are A-D, A, A+D

NOW, A to Q

A-D+A+A+D=30

A=10

Now, A+D.A.A-D=960

Put A=10 in above equation

then, D=2

therefore three numbers are 10-2,10,10+2

8,10,12

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