Question

Find three positive integers in ap such that their sum is 24 and product is 480​

Answer 1

Find three positive integers in A.P. such that their sum is 24 and their product is 480.

∴a−d+a+a+d=24.

3a=24.

∴a=8.

(a−d)(a)(a+d)=480.

(8−d)(8)(8+d)=480[∵a=8]

(8−d)(8+d)=60.

64−d2=60.

d2=±4 =±2.