Question

find three positive integers in APsuch there sum is 24 and there product is 480​

Answer 1

Answer:

Let the three terms be a - d, a, a + d

Sum = 24 Product = 480

∴a−



d+a+a+



d=24

3a=24

∴a=8

(a−d)(a)(a+d)=480

(8−d)(8)(8+d)=480[∵a=8]

(8−d)(8+d)=60

64−d

2

=60

d

2

=±

4

=±2

If a=8,d=2 the terms are

a−d=8−2=6,a=8,a+d=8+2=10

∴ the term are 6,8,10.

We will get the same values if we'll consider d=−2.