find three positive numbers in the ratio 2:3:5, the sum of whose squares is 950
Answers
Answered by
4
let the three numbers be 2A, 3A and 5A,
then
according to the question, we have
(2A)²+(3A)²+(5A)²=950,
4A²+9A²+25A²=950,
38A²=950,
then
A²=950/38,
A²=2,
then
A=5,
therefore
1st number=2×5=10,
2nd number=3×5=15,
3rd number=5×5=25
then
according to the question, we have
(2A)²+(3A)²+(5A)²=950,
4A²+9A²+25A²=950,
38A²=950,
then
A²=950/38,
A²=2,
then
A=5,
therefore
1st number=2×5=10,
2nd number=3×5=15,
3rd number=5×5=25
Answered by
5
Let the numbers be 2x , 3x and 5x
Therefore
4x² + 9x² + 25x² = 950
38x² = 950
x² = 950/38
x² = 25
x = 5
The numbers will be
1st number = 2x = 10
2nd number = 3x = 15
3rd number = 5x = 25
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