Question

find three prime numbers so thst their product is 31 times rheir sum​

Answer 1

Step-by-step explanation:

The prime numbers less than 31 are

[math]P=(2, 3, 5, 7, 11, 13, 17, 19, 23, 29)[/math]

As the sum is odd all three prime numbers must be odd, so [math]2[/math] to be discarded. Similarly, [math]29[/math] to be discarded as it's only 2 less than [math]31[/math].

So, we are left with

[math]P=( 3, 5, 7, 11, 13, 17, 19, 23)[/math]

To get addition of 3 prime number as [math]31[/math] , we are having four possible combination.

[math](3, 5, 23),[/math]

[math](5, 7, 19),[/math]

[math](3, 11, 17),[/math]

[math](7, 11, 13)[/math]

But question is asked about three consecutive prime numbers. So we are left with only solution of [math](7, 11, 13)[/math] which are consecutive prime numbers with their addition as [math]7+11+13=31[/math].

Hope this approach helps.