Question

find three rational number between 1 upon 4 and 1 upon 5​

Answer 1

To find 4 rational number between

$\frac{1}{4}and \frac{1}{5}</p><p>$

So, we have to multiply a mext consecutive number of the numbers required in the numerator and denominator.

Hence, we will multiply here (n+1)

and (n+1)=(3+1)=4.

So,we will multiply $\frac{4}{4}$ in both the fractions.

$\frac{1}{4} and \frac{1}{5}$

$\frac{1}{4} * \frac{4}{4} and \frac{1}{5}*\frac{4}{4}.$

now the numbers we will get are

$\frac{4}{16} and \frac{4}{20}$

Now, take LCM of these numbers.

LCM=80

now the fractions will be

$\frac{20}{80} and \frac{16}{80}$

Hence, the required fractions are

$\frac{17}{80} , \frac{18}{80} ,\frac{19}{80}$

Answer 2

Solution..

First rational no.

$\frac{1}{2} ( \frac{1}{4} + \frac{1}{5} )$

$\frac{1}{2} \times ( \frac{5 + 4}{20} )$

[LCM of 4 and 5 is 20]

$\frac{1}{2} \times \frac{9}{20}$

$\frac{9}{40}$

Second rational no.

$\frac{1}{2} \times ( \frac{9}{40} + \frac{1}{4})$

$\frac{1}{2} \times( \frac{9 + 10}{40} )$

[LCM of 4 and 40 is 40]

$\frac{1}{2} \times \frac{19}{40}$

$\frac{19}{80}$

Third rational no.

$\frac{1}{2} \times ( \frac{9}{40} + \frac{1}{5})$

$\frac{1}{2} \times( \frac{9 + 8}{40} )$

[LCM of 5 and 40 is 40]

$\frac{1}{2} \times \frac{17}{40}$

$\frac{17}{80}$