find three rational numbers between 0.285714bar and 0.428571bar
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0.29
0.3
0.4
these are three simple rational numbers
0.3
0.4
these are three simple rational numbers
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5
Solution :-
Given two numbers are 0.285714bar and 428571bar.
Let x = 0.285714bar
Then, x = 0.285714285714..........(1)
Since there are six repeating digits,
⇒ we will multiply both the sides of equation (1) by 1000000
⇒ x*1000000 = 0.285714285714*1000000
⇒ 1000000x = 285714.285714 .............(2)
Subtracting (1) from (2), we get.
⇒ 1000000x - x = 285714.285714 - 0.285714
⇒ 999999x = 285714
⇒ x = 285714/999999
⇒ x = 2/7
Let x = 0.428571bar
x = 0.428571428571 .............(1)
Since there are six repeating digits.
⇒ We will multiply both the sides of equation (1) by 1000000
⇒ (x*1000000) = (0.428571428571*1000000)
⇒ 1000000x = 428571.428571 ............(2)
Now, subtracting (1) from (2), we get.
⇒ 1000000x - x = 428571.428571 - 0.428571
⇒ 999999x = 428571
⇒ x = 428571/999999
⇒ x = 3/7
Now, we have to find three rational numbers between 2/7 and 3/7
⇒ Multiplying the denominators and numerators of both the fractions by 20, we get.
⇒ 2/7 = (2*20)/(7*20) = 40/140
⇒ 3/7 = (3*20)/(7*20) = 60/140
Three rational numbers between 40/140 and 60/140
= 42/140 ; 49/140 and 56/140
Answer.
Given two numbers are 0.285714bar and 428571bar.
Let x = 0.285714bar
Then, x = 0.285714285714..........(1)
Since there are six repeating digits,
⇒ we will multiply both the sides of equation (1) by 1000000
⇒ x*1000000 = 0.285714285714*1000000
⇒ 1000000x = 285714.285714 .............(2)
Subtracting (1) from (2), we get.
⇒ 1000000x - x = 285714.285714 - 0.285714
⇒ 999999x = 285714
⇒ x = 285714/999999
⇒ x = 2/7
Let x = 0.428571bar
x = 0.428571428571 .............(1)
Since there are six repeating digits.
⇒ We will multiply both the sides of equation (1) by 1000000
⇒ (x*1000000) = (0.428571428571*1000000)
⇒ 1000000x = 428571.428571 ............(2)
Now, subtracting (1) from (2), we get.
⇒ 1000000x - x = 428571.428571 - 0.428571
⇒ 999999x = 428571
⇒ x = 428571/999999
⇒ x = 3/7
Now, we have to find three rational numbers between 2/7 and 3/7
⇒ Multiplying the denominators and numerators of both the fractions by 20, we get.
⇒ 2/7 = (2*20)/(7*20) = 40/140
⇒ 3/7 = (3*20)/(7*20) = 60/140
Three rational numbers between 40/140 and 60/140
= 42/140 ; 49/140 and 56/140
Answer.
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