Math, asked by harsha116, 1 year ago

Find three smallest consecutive natural numbers such that the difference between one third of the largest and one fifth of the smallest is at least 3

Answers

Answered by Deepsbhargav
62
let's the number be
n, n+1 , n+2

according to question..

(n+2)/3 - (n/5) > 3

(5n+10-3n)/15 > 3

2n + 10 > 45

2n = 35

n = 17.5

integer greater than 17.5 is 18

thus the three smallest number satisfying the condition are.. "18,19 and 20"


I hope it will help you..

Attachments:
Answered by Rk123447
16

Answer:

Step-by-step explanation

x, x+1, x+2

1/3(x+2) - 1/5>3

5x +10-3x>45

2x>35

x>17.5

integer greater than 17.5 is 18

Then three smallest natural number in this question are 18;19;20

Similar questions