Find three smallest consecutive natural numbers such that the difference between one third of the largest and one fifth of the smallest is at least 3
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Answered by
62
let's the number be
n, n+1 , n+2
according to question..
(n+2)/3 - (n/5) > 3
(5n+10-3n)/15 > 3
2n + 10 > 45
2n = 35
n = 17.5
integer greater than 17.5 is 18
thus the three smallest number satisfying the condition are.. "18,19 and 20"
I hope it will help you..
n, n+1 , n+2
according to question..
(n+2)/3 - (n/5) > 3
(5n+10-3n)/15 > 3
2n + 10 > 45
2n = 35
n = 17.5
integer greater than 17.5 is 18
thus the three smallest number satisfying the condition are.. "18,19 and 20"
I hope it will help you..
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Answered by
16
Answer:
Step-by-step explanation
x, x+1, x+2
1/3(x+2) - 1/5>3
5x +10-3x>45
2x>35
x>17.5
integer greater than 17.5 is 18
Then three smallest natural number in this question are 18;19;20
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