Question

find three solution of following (i) 2x+3y=12
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Answer 1

✴Answer❤

➡the two solutions of the equation is (0,-4)(6,0).

✴step-by-step explanation:

➡given : Linear equation 2x-3y=122x−3y=12

To find : Two solutions of the linear equation?

Solution :

We can find the solution of the linear equation by putting x=0 and y=0 so that two points form which are the solution of the linear equation,

2x-3y=122x−3y=12

2(0)-3y=122(0)−3y=12

-3y=12−3y=12

y=-4y=−4

The points is (0,-4)

Put y=0 in the linear equation,

2x-3y=122x−3y=12

2x-3(0)=122x−3(0)=12

2x=122x=12

x=6x=6

The points is (6,0)

Therefore, The two solutions of the equation is (0,-4)(6,0).

Answer 2

The correct answer is  (0, 4), (6, 0) and (3, 2).

Given: The equation of line = 2x+3y=12.

To Find: Three solutions of this equation.

Solution:

For first solution put x = 0 and calculate the value of y.

2(0) + 3y = 12

3y = 12

y = 4

The first solution is (0, 4).

For second solution put y = 0 and calculate the value of x.

2x + 3(0) = 12

2x = 12

x = 6

The second solution is (6, 0).

For third solution put any random value of x lets say x = 3. Now calculate y.

2(3) + 3y = 12

6 + 3y = 12

3y = 6

y = 2

The third solution is (3, 2).

Hence, the solutions of this equation are (0, 4), (6, 0) and (3, 2).

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