Question

find three solutions for 3x + 6y = 3900 by giving values to x​​

Answer 1

Answer:

Dividing equation by 3, we get

x + 2y = 1300

Subtracting 2y from both side we get

x = 1300 – 2y

Putting y = –1300, 0 and 1300 we get

x = 1300 – 2 (–1300) = 1300 + 2600 = 3900

x = 1300 – 2(0) = 1300 – 0 = 1300

x = 1300 – 2(1300) = 1300 – 2600 = – 1300