Question

find three terms of an ap whose sum is 3 and product is 8​

Answer 1

Answer:

I guess the product is -8..then

Step-by-step explanation:

Let a- d,a and a+d be three terms in an AP such that

a-d+a+a+d=3

or,3a=3

or,a=1

and,(a-d)a(a+d)=-8

or,(1-d)1(1+d)=-8

or,1-d^2=-8

or,1+8=d^2

or,9=d^2

or,d=±3

when a=1&d=3,

a-d=1-3=-2

a=1

a+d=1+3=4

when a=1 &d=-3

a-d=1+3=4

a=1

a+d=1-3=-2

Hence the numbers are -2,1,4 or 4,1,-2.