Question

find three terms of the AP (a + b),(a+1)+b,(a+1)+(b+1)​

Answer 1

Step-by-step explanation:

Ap series :- any series is in AP when common difference is always constant

here given series

Given A.P ;

(a+b) , (a+1+b) , (b+1)

a = (a+b)

d = (a+1+b)-(a+b)

d = a+1+b-a-b

d = 1

d = (b+1)-(a+1+b)

1 = b+1-a-1-b

1 = -a

a = -1

hence terms are :

(a+b) +3a =4a+b or 4+b

=4a+b or 4+b(a+b)+4a =5a+b or 5+b

=5a+b or 5+b(a+b)+5a =6a+b or 6 +b