find three terms of the sequence tn=2+3n
(a) 6,8,10
(b) 5,7,9
(c) 8,12,16
(d) 5,8,11
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Answers
Answered by
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Step-by-step explanation:
tn=2+3n
put n=1
tn=2+3=5
put n=2
t2=2+6=8
put n=3
t3=2+9=11
hence the three terms are5,8,11
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