Question

Find three whole numbers a, b and c such that a + b + c = a *b *c, then what is the value of a 2 + b 2 + c 2 ?

Answer 1

Let a=1,b=2,c=3 then a+b+c=6
a*b*c=1*2*3=6
Therefore a^2 +b^2 +c^2 =1+4+9=14

Answer 2

The value of $a^{2} +b^{2} +c^{2}$ is $14$

Step-by-step explanation:

Given,

Find three whole numbers $a$, $b$ and $c$ such that $a + b + c = a \times b\times c$

We know,

First three digits addition value and multiplication value are same.

i.e,  First three digit are $1$,$2$ and $3$

So,

Addition of these three values is,

$(1+2+3)=6$

And multiplication value is,

$(1\times 2\times 3)=6$

Therefore,

We can take  $a$, $b$ and $c[/tex value are [tex]1$,$2$ and $3$

∴ $a^{2} +b^{2} +c^{2}$

$=1^{2} +2^{2} +3^{2}$

$=1+4+9$

$=14$

So, The value of $a^{2} +b^{2} +c^{2}$ is $14$