find threee consecutive even numbers whose sum is 186
Answers
Answered by
163
Let one of the even nos. be x.
so, other nos. are x+2 and x+4.
we have,
x+(x+2)+(x+4)= 186
⇒3x + 6 = 186
⇒ 3x = 180
⇒ x = 60
∴ The three consecutive even nos. are,
x= 60,
x+2 = 62, and
x+4 = 64
so, other nos. are x+2 and x+4.
we have,
x+(x+2)+(x+4)= 186
⇒3x + 6 = 186
⇒ 3x = 180
⇒ x = 60
∴ The three consecutive even nos. are,
x= 60,
x+2 = 62, and
x+4 = 64
Phillipe:
this will surely help u
Answered by
83
Hi friend,
Let the number be x
Second number be x+2
Third number be x+4
A.T.Q
x+x+2+x+4=186
3x+6=186
3x= 186-6
3x=180
x=180/3
x=60
Then,
One number is 60
Second number is 60+2=62
Third number is 60+4=64
The three numbers are 60,62,64.
Hope it helps...............
Let the number be x
Second number be x+2
Third number be x+4
A.T.Q
x+x+2+x+4=186
3x+6=186
3x= 186-6
3x=180
x=180/3
x=60
Then,
One number is 60
Second number is 60+2=62
Third number is 60+4=64
The three numbers are 60,62,64.
Hope it helps...............
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